Organic compound ‘A’ of molecular formula C₂H₆O liberates hydrogen gas with sodium metal. ‘A’ gives ‘B’ of formula C4H10O, when it reacts with concentrated H₂SO₄ at 413K. At 443K with concentrated H₂SO₄ ‘A’ gives compound ‘C’ of formula C₂H₄. This compound ‘C’ decolourises bromine water. What are ‘A’, ‘B’ and ‘C’?

Write a balanced equation using the correct symbols for these chemical reactions:

i) Action of hydrogen on ethene in the presence of nickel catalyst.

ii) Combustion of methane evolving carbondioxide and water.

iii) Dehydrogenation of ethanol.

iv) Decarboxylation of Sodium salt of ethanoic acid.

Look at the picture and identify what happens. Support your answer with equations.

i) How is B formed from A?

ii) What happens when acetic acid is treated with carbonate salt. Name the gas produced. What happens when this gas is treated with lime water?

iii) What happens when acetic acid is treated with ethanol in the presence of concentrated H₂SO₄? Give the equation.

Organic compounds ‘A’ and ‘B’ are the isomers with the molecular formula C₂H₆O.

Compound ‘A’ produces hydrogen gas with sodium metal, whereas compound ‘B’ does not. Compound ‘A’ reacts with acetic acid in the presence of concentrated H₂SO₄ bto form compound ‘C’ with a fruity flavour. What are the isomers ‘A’, ‘B’ and the compound ‘C’?

Organic compound ‘A’ of molecular formula C₂H₄O₂ gives brisk effervescence with sodium bicarbonate solution. Sodium salt of A on treatment with soda lime gives a hydrocarbon ‘B’ of molecular mass 16. It belongs to the first member of the alkane family. What are ‘A’ and ‘B’ and how will you prepare ‘A’ from ethanol?