Q14 of 33 Page 225

Organic compound ‘A’ of molecular formula C2H4O2 gives brisk effervescence with sodium bicarbonate solution. Sodium salt of A on treatment with soda lime gives a hydrocarbon ‘B’ of molecular mass 16. It belongs to the first member of the alkane family. What are ‘A’ and ‘B’ and how will you prepare ‘A’ from ethanol?

It is given that organic compound gives brisk effervescence with sodium bicarbonate solution.


i. As we know that when ethanoic acid reacts with sodium bicarbonate, it gives brisk effervescence of carbon dioxide.


Hence, the organic compound “A” must be ethanoic acid


(CH3COOH)


The reaction of ethanoic acid with a carbonate (Na2CO3) is:



ii. When sodium salt of ethanoic acid is heated with soda lime, methane (alkane) gas is formed.



Methane (B) formed belongs to the first member of the alkane family


iii. Preparation of ethanoic acid (A) from ethanol:


Ethanol undergoes oxidation with KMnO4 to form a carboxylic acid, i.e., ethanoic acid (A)


The reaction takes place is given below:



Thus, A is ethanoic acid and B is methane.


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