Construct a ∆ ABC in which CA = 6 cm, AB = 5 cm and BAC = 45⁰. Then construct a triangle whose sides are of the corresponding sides of a ∆ ABC.

For ∆ ABC

Step 1 : Draw the line of 5 cm with the help of scale and

and name it AB. Also draw the arc with the

help of compass from point A.

Step 2 : Open the compass at angle of 45⁰ with the help of

Protector. Mark the angle 0f 45⁰ on arc with the

help of compass from point E. Joint the arc with

point A and mark 6 cm on it.

Step 3 : Joint Point C with Point B.

For corresponding triangle

Step 1 : Draw any ray BX making an acute angle with BC on the side opposite to the vertex A.

Step 2 : Cut the BD in 5 equal parts starting from B.

Step 3 :Meet the point S with C and draw the angle equal to BSC from the O with the help of compass i.e., draw line parallel to SC.

Step 4 : Draw the line parallel to AC from point C₁ with help of compass.

∆ A₁BC₁ is our new triangle whose corresponding side is of the given triangle.