If the median of the following frequency distribution is 32.5. Find the values of f1 and f2.
Or
The marks obtained by 100 students of a class in an examination are given below.

Draw ‘a less than’ type cumulative frequency curves (orgive). Hence find median.
Sum of frequency = 40
f1 + 5 + 9 + 12 + f2 + 3 + 2 = 40
f1 + f2 = 9
l = lower limit of median class (30 – 40) = 30
n = number of observations = 31 + f1 + f2
cf = cumulative frequency of class preceding to the median
class = 14 + f1
f = frequency of the median class = 12
h = class size = 10


2.5 × 1.2 = 20 – 14 - f1
f1 = 3
f2 = 9 – 3
f2 = 6
OR
n = number of observations = 100
n/2 = 50
CF of median class = 56
l = lower limit of median class (25 – 30) = 25
cf = cumulative frequency of class preceding the median class = 31
f = frequency of the median class = 25
h = class size = 5

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Median = 28.8

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