If A is an invertible square matrix then │A-1│=?
B
We know that AA-1 =![]()
Taking determinant both sides
│AA-1│ = │I│
│A││A-1│ = │I│ (│AB│=│A││B│)
│A││A-1│ = 1 (│I│ = 1)
│A-1│= ![]()
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