Q40 of 98 Page 314

If A and B are invertible square matrices of the same order then (AB)^-1=?

(AB)(AB)^-1 = I

A^-1(AB)(AB)^-1 = IA^-1

(A^-1A)B (AB)^-1=A^-1

IB(AB)^-1 = A^-1

B(AB)^-1 = A^-1

B^-1B(AB)^-1 = B^-1 A^-1

I (AB)^-1 = B^-1A^-1

(AB)^-1 = B^-1A^-1

If A =then adj A=?

If A = and B is a square matrix of order 2 such that AB=I then B=?

If A=, then A^-1=?

If │A│=3 and A^-1=then adj A=?

If A and B are invertible square matrices of the same order then (AB)-1=?