Q5 of 118 Page 3

Write the range of the function f (x) = cos [x], where


[x]= -2


f(x)= cos [x]= cos (-2)


= cos 2


because cos(-x) = cos(x)


for-1 ≤x<0


[x]=-1


f(x)= cos[x]=cos (-1)


= cos 1


for 0 ≤x< 1


[x]=0


f(x)=cos 0 =1


for 1 ≤x<π/2


[x]=1


f(x)=cos1


Therefore, R(f) = {1, cos 1, cos 2}


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