If
, show that f(tanθ) = sin2θ.
Given ![]()
We need to prove that f(tanθ) = sin2θ.
We have ![]()
We know ![]()



However, cos2θ + sin2θ = 1

![]()
⇒ f(tanθ) = 2sinθcosθ
∴ f(tanθ) = sin2θ
Thus, f(tanθ) = sin2θ
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