If, find:

i.

ii. f(–2)

iii. f(1)

iv.

v.

Given

i.

When 0 ≤ x ≤ 1, f(x) = x

ii. f(–2)

When x < 0, f(x) = x²

⇒ f(–2) = (–2)²

∴ f(–2) = 4

iii. f(1)

When x ≥ 1,

∴ f(1) = 1

iv.

We have

When x ≥ 1,

v.

We know is not a real number and the function f(x) is defined only when x ∈ R.

Thus, does not exist.