Q11 of 122 Page 15

Mark the Correct alternative in the following:

If , then



Case I : x > 2



1 ≥ 0


It is true that 1 is always greater than 0 so case I is also true x > 2


Case II : x < 2



-1 ≥ 0


It is false that -1 is not greater than 0 so case II is also false.


So, the final solution is x > 2 i.e., x ∈ (2, ∞)

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