Solve the following linear inequations in R
3x + 9 ≥ –x + 19
Given 3x + 9 ≥ –x + 19
⇒ 3x + 9 – 9 ≥ –x + 19 – 9
⇒ 3x ≥ –x + 10
⇒ 3x + x ≥ –x + 10 + x
⇒ 4x ≥ 10
Thus, the solution of the given inequation is
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