Q14 of 292 Page 469

The pressure p and the volume V of a gas are connected by the relation, , where k is a constant. Find the percentage increase in the pressure, corresponding to a diminution of 0.5% in the volume.


Given: pv1/4 = k


%decrease in the volume = 1/2%s


∴


pv1/4 = k


taking log on both sides


log[pv1/4] = log a


log P + 1.4logV = log a


Differentiating both the sides we get


⇒


⇒


Multiplying both sides by 100.


⇒


⇒


⇒


%error in P = 0.7%.


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