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If 
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Given that y=cos-1(4x3-3x)
Let x=cos θ
⇒ θ=cos-1x
Then, y=cos-1(4cos3θ-3cosθ)
Using cos3θ=4cos3θ-3cosθ , we get
y=cos-1(cos3θ)=3=3cos-1x
Differentiating with respect to x, we get
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