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If 
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Given that y=sin-1(3x-4x3)
Let x=sin θ
⇒ θ=sin-1x
Then, y= sin-1(3sinθ -4sin3θ)
Using sin3θ=3sinθ -4sin3θ, we get
y=sin-1(sin3θ)=3θ=3sin-1x
Differentiating with respect to x, we get
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