If there is an error of 0.1% in the measurement of the radius of a sphere, find approximately the percentage error in the calculation of the volume of the sphere.
Volume of the sphere is given by = ![]()
Change in volume = ![]()
Given: Δr = 0.1
⇒ ![]()
⇒ ![]()
Percentage error
⇒ ![]()
= 0.3%
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.