Let's arrange sticks in a new arrangement and find the number of sticks required in the n-th position.
The new arrangement would be


Sticks in first arrangement (a) = 2
Sticks in second arrangement = 5
Common Difference (d) = 5 – 2 = 3
Sticks in n-th position = a + (n – 1) d
= 2 + (n – 1) (3)
= 2 + 3n – 3
= 3n – 1
the sticks required in n-th position are “3n – 1”
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