Let’s express following the expressions as sum of two squares:
i. ![]()
ii. ![]()
iii. ![]()
Formulas used:
(a + b)2 = a2 + 2ab + b2 [1]
(a – b)2 = a2 – 2ab + b2 [2]
i. 2(a2 + b)2
= 2a2 + 2b2
= a2 + b2 + a2 + b2
= a2 + 2ab + b2 + a2 – 2ab + b2
Using identities [1] and [2],
= (a + b)2 + (a – b)2
ii. 50x2 + 18y2
= 25x2 + 25x2 + 9y2 + 9y2
= 25x2 + 9y2 + 25x2 + 9y2
= (5x)2 + (3y)2 + (5x)2 + (3y)2
Using identities [1] and [2],
Here, a = 5x, b = 3y
= (5x)2 + 2(5x)(3y) + (3y)2 + (5x)2 – 2(5x)(3x) + (3x)2
= (5x + 3y)2 + (5x – 3y)2
iii. a2 + b2 + c2 + d2 + 2(ac – bd)
= a2 + b2 + c2 + d2 + 2ac – 2bd
Using identities [1] and [2],
= a2 + 2ac + c2 + b2 – 2bd + d2
= (a + c)2 + (b – d)2
Couldn't generate an explanation.
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