and
Let’s find out the square of the expressions given below using the above identities –
i. ![]()
ii. ![]()
iii. ![]()
iv. ![]()
i. (5x – 2y)2
Apply the formula (a-b)2 = a2 + b2 -2ab
Here a = 5x and b = 2y
= (5x)2 – 2(5x)(2y) + (2y)2
= 25x2 – 20xy + 4y2
ii. (7 + 2m)2
Using, (a + b)2 = a2 + 2ab + b2
Here, a = 7, b = 2m
= (7)2 + 2(7)(2m) + (2m)2
= 49 + 28m + 4m2
iii. (x + y + z)2
= (x + (y + z))2
Using, (a + b)2 = a2 + 2ab + b2
Here, a = x, b = y + z
= x2 + 2(x)(y + z) + (y + z)2
Again, using, (a + b)2 = a2 + 2ab + b2
Here, a = y, b = z
= x2 + 2xy + 2xz + y2 + z2 + 2yz
= x2 + y2 + z2 + 2xy + 2yz + 2xz
iv. (a + b – c – d)2
= (a + b – (c + d))2
Using, (A - B)2 = A2 - 2AB + B2
Here, A = a + b, B = c + d
= (a + b)2 – 2(a + b)(c + d) + (c + d)2
Using, (a + b)2 = a2 + 2ab + b2
= (a2 + b2 + 2ab) – 2(ac + ad + bc + bd) + (c2 + d2 + 2cd)
= a2 + b2 + c2 + d2 + 2ab – 2bc + 2cd – 2ad–2bd – 2ac
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.



