If the capacitors in the previous question are joined in parallel, the capacitance and the breakdown voltage of the combination will be

Given:

Two capacitors of capacitance C each and breakdown voltage V connected in parallel

Explanation:

The general formula for effective capacitance of a series combination of n capacitors is given by

The equivalent capacitance of two capacitors connected in parallel are given by

Where

C₁ is the capacitance of the capacitor C₁

C₂ is the capacitance of the capacitor C₂

Here C₁=C₂=C

Putting the values in the above formula, we get

∴ C_eq=C+C=2C

Since, potential difference across capacitors in parallel are equal

Therefore voltage across the system is equal to the voltage across a single capacitor.

Therefore, breakdown voltage of the combination =V