Q10 of 94 Page 166

Find the charge supplied by the battery in the arrangement shown in the figure.


Given V= 10V


C1=5


C2=6


Formula used :


Charge supplied by the battery is



Where


C is the capacitance of the capacitor


V is the voltage across the potential difference


Q is the Charge on the capacitor


First, we have to calculate the capacitance C .To do this short circuit the voltage source and open circuit the current source. We don’t have any current sources over here. So short circuit the Voltage source. Then two capacitors will come to parallel. In parallel connection of the capacitor we add the capacitor values.



Equalent Capacitance is





Charge Q can be calculated as



Charge supplied by the battery is


More from this chapter

All 94 →
8

Find the charge appearing on each of he three capacitors shown in the figure.


 9

Take C1 = 4.0 μF and C2 = 6.0 μF in figure. Calculate the equivalent capacitance of the combination between the points indicated.


 11

The outer cylinders of two cylindrical capacitors of capacitance 2.2 μf each are kept in contact, and the inner cylinders are connected through a wire. A battery of emf 10V is connected as shown in the figure. Find the total charge supplied by the battery to the inner cylinders.


 12

Two conducting spheres of radii R1 and R2 are kept widely separated from each other. What is their individual capacitance? If the spheres are connected by a metal wire, what will be the capacitance of the combination? Think in terms of series-parallel connections.