Identify the products A and B formed in the following reaction:

(a) CH₃—CH₂—CH=CH—CH₃+HCl → A + B

Compound ‘A’ with molecular formula C₄H₉Br is treated with aq. KOH solution. The rate of this reaction depends upon the concentration of the compound ‘A’ only. When another optically active isomer ‘B’ of this compound was treated with aq. KOH solution, the rate of reaction was found to be dependent on concentration of compound and KOH both.

(i) Write down the structural formula of both compounds ‘A’ and ‘B’.

(ii) Out of these two compounds, which one will be converted to the product with inverted configuration?

Write the structures and names of the compounds formed when compound ‘A’ with molecular formula, C₇H₈ is treated with Cl₂ in the presence of FeCl₃.

Which of the following compounds will have the highest melting point and why?

(I)

(II)

(III)

Write down the structure and IUPAC name for neo-pentylbromide.