Q15 of 26 Page 1

(i) Predict the number of unpaired electrons in the tetrahedral [MnBr4]2- ion.


(ii) Draw structures of geometrical isomers of [Co(NH3)4Cl2]+.


(iii) Write the formula for the following coordinate compound:


Amminebromidochloridonitrito-N-platinate(II)


(i)


• [MnBr4]2- is a geometrically tetrahedral coordination compound where , Mn has a +2 state ( 4 Br exerts -4 charge and the charge of whole complex is -2 hence charge of Mn =4 – 2 = +2 )


• Atomic no. Of Mn is 25 hence, Mn(II) has 23 electrons hence it has 5 valence shell electrons , 3d5 valence configuration.


Hence the number of unpaired electrons in Mn(II) is 5.


(ii)


• The structures of geometrical isomers(cis and trans) of the given coordination complex [Co(NH3)4Cl2]+ which has a square planar structure is -



(iii)


• The formula for Amminebromidochloridonitrito-N-platinate(II) is


[PtClBr(NO2)NH3]-


The oxidation state of Platinum is II.


More from this chapter

All 26 →
13

Write the Nernst equation and calculate the emf for the following cell at 298 K:

Mg(s) / Mg2+ (0.001 M) // Cu2+ (0.0001 M) / Cu(s)


How does Ecell vary with the concentration of both Mg2+ and Cu2+ ions? (Given E0 cell= 2.71 V).


 14

Explain the following observations giving appropriate reasons:

(i) Ozone is thermodynamically unstable with respect to oxygen. .


(ii) The HEH bond angle of the hydrides of group 15 elements decrease as we move down the group.


(iii) Bleaching effect of chlorine is permanent.


 16

Explain what is observed when

(i) Silver nitrate solution is added to potassium iodide solution.


(ii) The size of the finest gold sol particles increases in the gold sol.


(iii) Two oppositely charged sols are mixed in almost equal proportions.


 17

(i) In the following pairs of halogen compounds, which would undergo SN1 reaction


faster? Explain.



(ii) Amongst the isomeric dihalobenzenes which isomer has the highest melting point and why?


(iii) Arrange the following haloalkanes in the increasing order of density. Justify your answer.


CCl4, CH2Cl2 and CHCl3.