Particles of masses 2M, m and M are respectively at points A, B and C with AB = 1/2 (BC). m is much - much smaller than M and at time t = 0, they are all at rest (Fig. 8.1). At subsequent times before any collision takes place:

We know that gravitational force between two masses separated by a distance r is given by
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Now,
Force due to 2M at A on B =
towards A
Force due to M at C on B =
towards C
Therefore, net force on B
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Towards A
Therefore, m will move towards A
Therefore (c) is the correct option
Couldn't generate an explanation.
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