Six point masses of mass m each are at the vertices of a regular hexagon of side l. Calculate the force on any of the masses.
Given
Side of hexagon = l
The force on the masses will be the resultant of the forces of all the other masses. Let the masses be m each. Now the distance AC is given by the parallelogram law i.e.
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Due to symmetry we have AC = AE = ![]()

Now, for AD we have
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Now the force on mass at A due to b is
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Also
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The force on mass A due to C is
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Also due to symmetry, we have
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The force on mass at A due to mass at D is
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Now, the forces Fae and Fac make equal angles with the direction AD viz. 30°, and therefore by parallelogram law of vector addition their resultant is along AD and therefore the magnitude of the resultant,
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Similarly, Fab and Faf also make equal angles with AD viz. 60° and therefore they are also along AD and
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Therefore, the net force on mass at A will be
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