Q37 of 38 Page 63

Earth’s orbit is an ellipse with eccentricity 0.0167. Thus, earth’s distance from the sun and speed as it moves around the sun varies from day to day. This means that the length of the solar day is not constant through the year. Assume that earth’s spin axis is normal to its orbital plane and find out the length of the shortest and the longest day. A day should be taken from noon to noon. Does this explain variation of length of the day during the year?

Given


The eccentricity of earth’s orbit e = 0.0167


Let the earth - sun distance at the aphelion and perihelion be ra and rp respectively, and the angular velocity at those points be ωa and ωp. Now since the angular momentum of the earth is conserved we have




Now, from the ellipse we have



Where a is the semi - major axis of the ellipse




Since e = 0.0167



Now let the mean angular velocity of earth corresponding to the mean solar day be ω, then



And since the mean angular velocity is the geometric mean of the two, we have



Now we know that the mean solar day corresponds to 1° on the orbit of earth. A mean solar day has 24 h for which the earth rotates 361°. Thus for aphelion the earth rotates 361.034° and hence the time for the day is 24 hours and 8.1 seconds, and the for the perihelion the earth rotates 359.96° and the time is 23 hours and 52 seconds. Thus the longest day is 8.1 seconds long and the shortest day is 8 seconds shorter. However, the variation of length of day in the year is not explained by this phenomenon as the total time of the day still remains around 24 hours, while the amount of time the sun is visible changes.


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