Three copper blocks of masses M1, M2 and M3 kg respectively are brought into thermal contact till they reach equilibrium. Before contact, they were at T1, T2, T3 (T1 > T2 > T3 ). Assuming there is no heat loss to the surroundings, the equilibrium temperature T is (s is specific heat of copper)
It is given that there is no heat loss in the surrounding
and equilibrium temperature in the system is T.
It is also given s is the specific heat of the copper
Let us assume ![]()
∴ heat loss by
= heat gain by
+ heat gain by ![]()
⇒ ![]()
⇒ ![]()
∴ ![]()
option (b) is correct.
Couldn't generate an explanation.
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