Consider a P-V diagram in which the path followed by one mole of perfect gas in a cylindrical container is shown in Fig. 12.9.
(a) Find the work done when the gas is taken from state 1 to state 2.
(b) What is the ratio of temperature T1/T2, if V2 = 2V1?
(c) Given the internal energy for one mole of gas at temperature T is (3/2) RT, find the heat supplied to the gas when it is taken from state 1 to 2, with V2 = 2V1.

a. We know that work done is given by an ideal gas is given by,
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According to question,
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Work done by the gas=![]()
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...............(1)
Since ,![]()
Putting the value equation 1 becomes,
Work done=![]()
c. To relate the temperature we have to modify the equation
in terms of T.
From ideal gas equation we know,
PV=nRT
Where,
P=pressure
V=volume
T=absolute temperature
n=number of moles of gas
R=ideal gas constant
Here, n=1 (given)
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But ,![]()
So, comparing both we get,
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Or ![]()
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=new constant=C
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For state 1 let, ![]()
For state 2 let, ![]()
Equating both we get,
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Now, givenV2 = 2V1

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c.
![]()
Where,
is change in internal energy given by ![]()
n = No. Of moles
Cv= Specific heat capacity at constant volume.
= Change in temperature
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...........(2)
W=![]()
AlsoV2 = 2V1
W=![]()
W=![]()
W=
............(3)
Since,
and n=1
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Putting the value in equation 3
W=![]()
Now,
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