A cycle followed by an engine (made of one mole of an ideal gas in a cylinder with a piston) is shown in Fig. 12.11. Find heat exchanged by the engine, with the surroundings for each section of the cycle. (Cv = (3/2) R)
AB: constant volume
BC: constant pressure
CD: adiabatic
DA: constant pressure

According to 1st law of thermodynamics which states that the change in internal energy of a system is equal to the heat added to the system minus work done by the system.
![]()
As process AB is isochoric Work done by the system is given by
and for isochoric process it is ![]()
........(1)
And we know ![]()
Where, n = No. Of moles i.e. one in this case
Cv= Specific heat capacity at constant volume i.e.
in this case
= Change in temperature
=
........(2)
Using Ideal gas eq. i.e. PV=nRT
We can replace R
by PBVB and R
by PAVA
VA = VB (Given in the question)
Substituting the values in eq. 2 we get
= ![]()
Using eq. 1
Q= ![]()
Now Process BC is isobaric i.e. Constant Pressure
Work done by the system is given by
as P is constant
W =
=
(
)
We know
by 1st law of thermodynamics
Q =
+
since, ![]()
Here n = 1 mole
Cv=
R
=
+
(
)
Using Ideal gas eq. i.e. PV=nRT
We can replace R
by PCVC and R
by PBVB
PB = PC (Given in the question)
=
+
(
)
Q = ![]()
Process CD is adiabatic
=0
Again Process AD is isobaric i.e Constant Pressure
Work done by the system is given by
as P is constant
W =
=
(
)
We know
by 1st law of thermodynamics
Q =
+
since, ![]()
Here n = 1 mole
Cv=
R
=
+
(
)
Using Ideal gas eq. i.e. PV=nRT
We can replace R
by PAVA and R
by PDVD
PA= PD (Given in the question)
=
+
(
)
Q = ![]()
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