Q3 of 51 Page 330

A bulb rated 60W at 220V is connected across a household supply of alternating voltage of 220V. Calculate the maximum instantaneous current through the filament

Given that: Power (P) = 60W

Alternate Voltage (V) =220V


Now, power can be expressed as



Therefore,


Then instantaneous voltage is



Thus, the maximum instantaneous current through the filament



More from this chapter

All 51 →
1

Find the time required for a 50 Hz alternating current to change its value from zero to the rms value.

 2

The household supply of electricity is at 220 V (rms value) and 50 Hz. Find the peak voltage and the least possible time in which the voltage can change from the rms value to zero.

 4

An electric bulb is designed to operate at 12 volts DC. If this bulb is connected to an AC source and given normal brightness, what would be the peak voltage of the source?

 5

The peak power consumed by a resistive coil when connected to an AC source is 80W. Find the energy consumed by the coil in 100 seconds which is many times larger than the time period of the source.