The peak power consumed by a resistive coil when connected to an AC source is 80W. Find the energy consumed by the coil in 100 seconds which is many times larger than the time period of the source.
Given that: Peak power (
= 80 W
Then, instantaneous power is
![]()
The energy consumed by the coil in time t=100 seconds will be
= P × t = 40 × 100
= 4000J
Energy consumed = 4.0KJ
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.