Q8 of 51 Page 330

A capacitor of capacitance 10 μF is connected to an oscillator giving an output voltage ϵ = (10V) sin ωt. Find the peak currents in the circuit for ω = 10 s–1, 100 s–1, 500 s–1, 1000 s–1.

Capacitance of the capacitor C=10 μF,


Output voltage of the oscillator ϵ = (10V) sin ωt.


On comparing the output voltage of the oscillator with



We get Peak voltage


For a capacitive circuit,


Reactance,


Here, is angular frequency,


C is capacitance of capacitor,


Peak current


{a} At


Peak current





{b} At


Peak current





{c} At


Peak current





{d} At


Peak current





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