A Sonometer wire is vibrating in resonance with a tuning fork. Keeping the tension applied same; the length of the wire is doubled. Under what conditions would the tuning fork still be in resonance with the wire?
When wire of length L is made to vibrate, its resonance frequency in nth mode after stretching it by tension T, then Frequency ![]()
[Here, m= mass per unit length of stretched wire]
The two given cases are:
---------------------- (i)
---------------------- (ii)
According to question;
(Mass of wire m is same in both cases)
![]()
Equation (i) divided by Equation (ii);

Since, the turning forks in the both cases are also same.
.
.
Hence, when the length of wire is doubled, the number of harmonic wave also doubles for same resonant frequency.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.