The earth has a radius of 6400 km. The inner core of 1000 km radius is solid. Outside it, there is a region from 1000 km to a radius of 3500 km which is in molten state. Then again from 3500 km to 6400 km the earth is solid. Only longitudinal (P) waves can travel inside a liquid. Assume that the P wave has a speed of 8 km s-1 in solid parts and of 5 km s-1 in liquid parts of the earth. An earthquake occurs at some place close to the surface of the earth. Calculate the time after which it will be recorded in a seismometer at a diametrically opposite point on the earth if wave travels along diameter?
Given:
Speed of longitudinal wave in solid = 8 kms-1
Speed of longitudinal wave in liquid = 5 kms-1
When the wave travels across the earth towards the core, it will pass the liquid region and the two solid regions. The first solid region starting from the crust has a radial distance of
![]()
For the molten region the radial distance is
![]()
And for the solid region of the core the distance is
![]()
The time taken to travel to the centre of earth from the crust is therefore,
![]()
where vs and vl are the velocities of the longitudinal wave in solid and liquid respectively.
![]()
To travel to a diametrical opposite point the time will be equal to 2t = 1975 s. Therefore, the seismometer will record the earthquake after 1975 seconds after the earthquake initiates.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
