A tuning fork vibrating with a frequency of 512Hz is kept close to the open end of a tube filled with water (Fig. 15.4). The water level in the tube is gradually lowered. When the water level is 17cm below the open end, maximum intensity of sound is heard. If the room temperature is 20° C, calculate
(a) speed of sound in air at room temperature
(b) speed of sound in air at 0° C
(c) if the water in the tube is replaced with mercury, will there be any difference in your observations?

Given:
Frequency of tuning fork = 512 Hz
Water level below open end = 17 cm
The water acts as a reflective surface for the wave, therefore the tube behaves like an organ pipe. When the water level is such that the frequency of the wave matches the resonant frequency of the organ pipe the maximum sound is heard.
(a) Since at 17 cm maximum intensity of sound is heard, it corresponds to amplitude of the wave. For the first harmonic the length of the organ pipe equals one-fourth the wavelength of the wave. Hence,
![]()
Where, l is the length of the pipe and λ is the wavelength
![]()
Now velocity of wave
![]()
where f is the frequency of the wave.
![]()
(b) We know that velocity of air is given by

where γ is the ratio of specific heat at constant pressure to specific heat at constant volume for air, R is the universal gas constant, T is temperature and M is the mass of the gas. Keeping everything constant except temperature,
![]()
Let the velocity of sound in air at 0° C be v0 and the velocity at temperature 20° be v20, then


![]()
![]()
(c) When water is replaced with mercury all the observations will remain same, however mercury is more reflective than water and therefore the intensity of the sound heard will be increased.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

