Q39 of 118 Page 352

The separation between a node and the next antinode in a vibrating air column is 25 cm. If the speed of sound in air is 340 m s-1, find the frequency of vibration of the air column.

Given:
Separation between the node and anti-node = 25 cm


Speed of sound in air



Frequency of vibration of the air column


The distance between two nodes or anti-nodes is .


We have:




Also,




Hence, the frequency of vibration of the air column is 340 Hz.


More from this chapter

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37

A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = 340 ms-1.

 38

In a standing wave pattern in a vibrating air column, nodes are formed at a distance of 4.0 cm. If the speed of sound in air is 328 m s-1, what is the frequency of the source?

 40

A cylindrical metal tube has a length of 50 cm and is open at both ends. Find the frequencies between 1000 Hz and 2000 Hz at which the air column in the tube can resonate. Speed of sound in air is 340 m s-1.

 41

In a resonance column experiment, a tuning fork of frequency 400 Hz is used. The first resonance is observed when the air column has a length of 20.0 cm and the second resonance is observed when the air column has a length of 62.0 cm. (a) Find the speed of sound in air. (b) How much distance above the open end does the pressure node form?