Two successive resonance frequencies in an open organ pipe are 1944 Hz and 2592 Hz. Find the length of the tube. The speed of sound in air is 324 m s-1.
Given:
Velocity of sound in air ![]()
Let
be the length of the resonating column.
Then, the frequencies of the two successive resonances will be:
And
.
As per the question,


So,



Hence, the length of the tube is 25 cm.
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