Q47 of 118 Page 352

Two successive resonance frequencies in an open organ pipe are 1944 Hz and 2592 Hz. Find the length of the tube. The speed of sound in air is 324 m s-1.

Given:
Velocity of sound in air



Let
be the length of the resonating column.



Then, the frequencies of the two successive resonances will be:


And .


As per the question,




So,





Hence, the length of the tube is 25 cm.


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