Given the ground state energy E0 = – 13.6 eV and Bohr radius a0 = 0.53 Å. Find out how the de Broglie wavelength associated with the electron orbiting in the ground state would change when it jumps into the first excited state.
Ground state energy of the electron= E0 = -13.6 eV
When the electron will jump from ground state to first excited state, then the energy of the electron will be
![]()
Now, we know that De Broglie wavelength associated with the particle is given by


![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.