Q17 of 26 Page 1

A cyclotron’s oscillator frequency is 10 MHz. What should be the operating magnetic field for accelerating protons? If the radius of its ‘dees’ is 60 cm, calculate the kinetic energy (in MeV) of the proton beam produced by the accelerator.

Oscillator frequency, f = 10 MHz = 107 Hz = Be/2πm


Where e = charge on a proton = 1.6 × 10-19 C


And m = mass of a proton = 1.67 × 10-27 kg


The applied magnetic field, B = 2mf/e


=


= 0.66 T


Radius of dees, R = 0.6 m


Kinetic energy of the proton beam = B2e2R2/2m


=


= 1.2 × 10-12 J


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