In Young’s double slit experiment, the two slits are separated by a distance of 1 �5 mm and the screen is placed 1 m away from the plane of the slits. A beam of light consisting of two wavelengths 650 nm and 520 nm is used to obtain interference fringes. Find
the distance of the third bright fringe for λ = 520 nm on the screen from the central maximum.
the least distance from the central maximum where the bright fringes due to both the wavelengths coincide.
Consider the following diagram.
D = 1m; d = 1.5 × 10-3 m; λ1 = 650 × 10-9 m; λ2 = 520 × 10-9 m

Let y be the distance of the third bright fringe from the central maxima.
![]()
Let that the ‘n’th bright fringe of 650 nm wavelength coincides with ‘n+1’th bright fringe of 520 nm wavelength at a distance y from the central maximum.
![]()
![]()
![]()
![]()
![]()
![]()
Distance from central maxima = ![]()
![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
