Q11 of 40 Page 1

ABC is an equilateral triangle of side 2a, then length of one of its altitude is____.



We have,


AB = 2a


BC = 1/2 × 2a = a


In ΔACB, By Pythagoras theorem


AB2 = AC2 + BC2


⇒ (2a)2 = AC2 + a2


⇒ 4a2 = AC2 + a2


⇒ AC2 = 3a2


⇒ AC = √3 a


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