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Q22 of 40 Page 1

The rod AC of a TV disc antenna is fixed at right angles to the wall AB and a rod CD is supporting the disc as shown in fig. 4. If AC = 1.5 m long and CD = 3 m, find (i) tan θ (ii) sec θ + cosec θ.


We have,


⇒ sin θ = 1.5/3 = 1/2


⇒ θ = 30°


(i)


(ii)



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Find the mean of the following distribution:

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Questions · 40
Set-II
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