The rod AC of a TV disc antenna is fixed at right angles to the wall AB and a rod CD is supporting the disc as shown in fig. 4. If AC = 1.5 m long and CD = 3 m, find (i) tan θ (ii) sec θ + cosec θ.

We have,
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⇒ sin θ = 1.5/3 = 1/2
⇒ θ = 30°
(i) ![]()
(ii) ![]()

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