The following table gives production yield per hectare (in quintals) of wheat of 100 farms of a village :
Change the distribution to 'a more than' type distribution and draw its ogive.
OR
The median of the following data is 525. Find the values of x and y, if total



Plot points (40, 100) (45, 96) (50, 90) (55, 74) (60,54) (65, 24) on a graph

OR

Given Median =525
Then, median Class = 500-600
the lower limit (l) = 500
cumulative frequency of the class preceding 500-600(cf) = 36 + x
frequency of the median class 500-600 = 20,
class size (h) = 100
Total frequencies (n) = 100
So, 76 + x + y = 100
⇒ x + y = 100 – 76
⇒ x + y = 24 …(i)
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Using the formula,
,we have
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⇒ 25 = (14 – x) × 5
⇒5 = 14 – x
⇒ x = 9
Putting the value of x in eq. (i), we get
⇒ 9 + y = 24
⇒ y = 24 – 9
⇒ y = 15
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