Find a quadratic polynomial whose zeroes are reciprocals of the zeroes of the polynomial f(x)=a x2+bx + c, a ≠ 0, c ≠ 0
OR
Divide the polynomial f(x)=3 x2-x3-3 x+5 by the polynomial g(x)=x-1-x2 and verify the division algorithm.
ax2 + bx + c, let its zeroes be α and β we have to find a quadratic polynomial whose zeroes are ![]()
Now , to form equation we need to find 
∴ Required quadratic equation will be

Now,


According to division algorithm
F(x) = g(x). q(x) + r (x)
q(x) = - x2 + x -1
q(x) = x-2
r(x) = 3
RHS = (-x2+x-1)(x-2)+3
= -x3+2x2+x2-2x-x+2+3
= -x3 +3x2-3x+5
= LHS
Hence verified
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.