Find the lateral curved surface area of a cylindrical petrol storage tank that is 4.3 m in diameter and 4.5 m high. How much steel was actually used, if
of steel actually used was wasted in making the closed tank?
Given,
Diameter of cylindrical tank = 4.3 m
Radius of tank = ![]()
Height of tank = 4.5 m
Lateral curved surface area of tank = 2πrh =
m2
Let total steel used in making of tank = X m2
Wasted steel =
m2
Actual steel used = X-
2
∴ ![]()
=![]()
= x = ![]()
Couldn't generate an explanation.
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