Find the area of a trapezium whose parallel sides are 9 cm and 6 cm respectively and the distance between these sides is 8 cm.

Given
AB = a = 9 cm
DC = b = 6 cm
Height (h) = 8 cm
We know that area of trapezium is
x (sum of parallel sides) x height
Therefore, Area of trapezium ABCD =
x (AB + DC) x h =
x (9 + 6) x 8 = 60 cm2
Area of Trapezium ABCD = 60cm2
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