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10. Area
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Q9 of 83 Page 367

Prove that area of a triangle = X base X altitude.


We know that when a parallelogram and a triangle lie on same base and between same parallel lines then, area of the triangle is half the area of the parallelogram.


Consider the figure,


Here,


Area(ΔABF) = 1/2 Area(||gm ABCD) (From above statement) –1


Area(||gm ABCD) = Base× Height –2


Sub –2 in –1


Area(ΔABF) = 1/2 × Base× Height


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7

Find the area of the trapezium whose parallel sides are 14 cm and 10 cm and whose height is 6 cm.

8

Show that the median of a triangle divides it into two triangles of equal area.

10

In the adjoining figure, ABCD is a quadrilateral in which diagonal BD = 14cm. If AL ⊥ BD and CM ⊥ BD such that AL = 8 cm and CM = 6 cm, find the area of quad. ABCD.

11

In the adjoining figure, ABCD is a quadrilateral. A line through D, parallel to AC, meets BC produced in P. Prove that ar(∆ABP) = ar(quad. ABCD).

Questions · 83
10. Area
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