Q5 of 83 Page 351

Calculate the area of trap. PQRS, given in Fig. (ii).


Given :- Right trapezium


RS = 8 cm


PT = 8cm


TQ = 8 cm


RQ = 17 cm


Here PQ = PT + TQ = 8 + 8 = 16


We know that area of trapezium is x (sum of parallel sides) x height


That is x (AB + DC) x RT


Consider TQR


By Pythagoras theorem


RQ2 = TQ2 + RT2


172 = 82 + RT2


RT2 = 17 2 - 82 = 289 – 64 = 225


RT = 15 cm


Area of trapezium = x (RS + PQ) x RT


= x (8 + 16) x 15 = 180 cm2


Area of trapezium PQRS = 180cm2

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