Q9 of 39 Page 207

The length of the fence of a trapezium-shaped field ABCD is 130 m and side AB is perpendicular to each of the parallel sides AD and BC. If m, m and m, find the area of the field.

Given


Length of parallel sides


AD = 42 m


BC = 54 m


Given that total length of fence is 130 m


That is AB + BC +CD +DA = 130


AB + 54 + 19 + 42 = 130


Therefore AB = 15


Height (AB) = 15 m


We know that area of trapezium is × (sum of parallel sides) × height


Therefore Area of trapezium = × (42 + 54) × 15 = 720 m2


More from this chapter

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7

The area of a trapezium is 180 cm2 and its height is 9 cm. If one of the parallel sides is longer than the other by 6 cm, find the two parallel sides.

 8

In a trapezium-shaped field, one of the parallel sides is twice the other. If the area of the field is 9450 m2 and the perpendicular distance between the two parallel sides is 84 m, find the length of the longer of the parallel sides.

 10

In the given figure, ABCD is a trapezium in which cm,

cm and cm. find the area of the trapezium.


 11

The parallel sides of a trapezium are 20 cm and 10 cm. Its nonparallel sides are both equal, each being 13 cm. Find the area of the trapezium.