In the given figure, ABCD is a quadrilateral in which
cm,
and
such that
cm and
cm. find the area of quad. ABCD.

Given: A quadrilateral ABCD
and ![]()
AC = 24 cm
BL = 8 cm
DM = 7 cm
Here,
Area (quad. ABCD) = area (
ABC) + area (
ADC)
Area of triangle =
× (base) × (height).
Therefore
Area of quad ABCD =
× (AC) × (BL) +
× (AC) × (DM)
=
× (24) × (8) +
× (24) × (7) = 96 + 84 = 180 cm2
Therefore area of the quadrilateral ABCD is 180 cm2
Couldn't generate an explanation.
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