Q2 of 39 Page 210

In the given figure, ABCD is a quadrilateral-shaped field in which diagonal BD is 36 m, and such that m and m. Find the area of the field.

Given: A quadrilateral ABCD


and


AL = 19 cm


BD = 36 cm


CM = 11 cm


Here,


Area (quad. ABCD) = area (ABD) + area (ACD)


Area of triangle = × (base) × (height).


Therefore


Area of quad ABCD = × (BD) × (AL) + × (BD) × (CM)


= × (36) × (19) + × (36) × (11) = 342 + 198 = 540 cm2


Therefore area of the quadrilateral ABCD is 540 cm2.


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